1.0419 (L355)
Classification
| Country |
Section |
Category |
| Germany |
Non-alloy Steels |
Steels with Average 0,12% =< C < 0,25% or 400 MPa = < Rm < 500 MPa |
Chemical composition
| Standard |
Fe, % |
Si, % |
Mn, % |
P, % |
C, % |
S, % |
|---|
| EN 10224 |
> 97.575 |
< 0.55 |
< 1.6 |
< 0.03 |
< 0.22 |
< 0.025 |
Information on suppliers
Mechanical properties at 20 °C
| Rolling |
Standard |
Size, mm |
Tension |
Classifiers |
$$\sigma _{U}$$, $$MPa$$ |
$$\sigma_{0.2}$$, $$MPa$$ |
$$\epsilon_{L (L_0 = 5.65\sqrt{S_o})}$$, % |
$$\epsilon_{T (L_0 = 5.65\sqrt{S_o})}$$, % |
Treatment |
|---|
|
|
|
|
|
500–650 |
345–355 |
21 |
19 |
|
Standards
Description of chemical elements
| Element |
Units of measurement |
Description |
| Fe |
% |
Iron |
| Si |
% |
Silicon |
| Mn |
% |
Manganese |
| P |
% |
Phosphorus |
| C |
% |
Carbon |
| S |
% |
Sulfur |
Description of mechanical properties
| Parameter |
Units of measurement |
Description |
| $$\sigma_{0.2}$$ |
$$MPa$$ |
Tensile stress required to produce a total elongation of 0.2% |
| $$\sigma _{U}$$ |
$$MPa$$ |
Ultimate tensile strength |
| $$\epsilon_{L (L_0 = 5.65\sqrt{S_o})}$$ |
% |
Elongation at break (longitudinal) (for L0 = 5.65√So) |
| $$\epsilon_{T (L_0 = 5.65\sqrt{S_o})}$$ |
% |
Elongation at break (transverse) (for L0 = 5.65√So) |